find area of iscosceles triangle whose perimeter is 64 and its perpendicular is 8 cm
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Step-by-step explanation:
it's perpendicular= 8 cm
and ATQ,
it is an isosceles triangle so it's other side will also be = 8 cm
perimeter given = 64 cm
also, perimeter = sum of all three sides
64 = 8+8+base
base = 64-16
base = 48 cm
find the area by heron's formula or draw an altitude of the triangle and find the height. then area = 1/2 × base × height
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