find area of major and miror sector of circle radius 21 cm angle60
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= 22 cm. Area of sector OACB =
In ΔOAB, ∠OAB = ∠OBA (As OA = OB) ∠OAB + ∠AOB + ∠OBA = 180° 2∠OAB + 60° = 180° ∠OAB = 60° ∴ ΔOAB is an equilateral triangle. Area of ΔOAB =
Area of segment ACB = Area of sector OACB − Area of ΔOAB.
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