Find area of rhombus whose diagonals are 10cm &
8cm
Answers
Answered by
3
area of rhombus = diago. 1×diago.2/2
=10×8/2
=40cm²ans.
=10×8/2
=40cm²ans.
Nithishmahi:
Can u answer my new question
now by using area of triangle for both and adding it
we get 1/2 diago.1×1/2diaonal2 + 1/2diagonal 2 ×1/2diaginal 1
Ok bro I understand . Plz answer my new question
by adding -- diago.1×diago2/2
ask
In quadrilateral ABCD the bisector of angleC & angleD intersect at O. Prove that angleCOD=(angleA+angleB)
Plz answer it
are log kar rahe h use
dekh lo jaa ke
Answered by
1
area of rhombus=1/2×product of diagonal =1/2×10×8=40cm^2
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