Math, asked by Nithishmahi, 1 year ago

Find area of rhombus whose diagonals are 10cm &
8cm

Answers

Answered by Mather

area of rhombus = diago. 1×diago.2/2
=10×8/2
=40cm²ans.

Nithishmahi: Can u answer my new question

Mather: now by using area of triangle for both and adding it

Mather: we get 1/2 diago.1×1/2diaonal2 + 1/2diagonal 2 ×1/2diaginal 1

Nithishmahi: Ok bro I understand . Plz answer my new question

Mather: by adding -- diago.1×diago2/2

Mather: ask

Nithishmahi: In quadrilateral ABCD the bisector of angleC & angleD intersect at O. Prove that angleCOD=(angleA+angleB)

Nithishmahi: Plz answer it

Mather: are log kar rahe h use

Mather: dekh lo jaa ke

Answered by deepak530

area of rhombus=1/2×product of diagonal =1/2×10×8=40cm^2

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