Question

find area of semicircular park whose perimeter is 360m

Answer 1

Solution:-

Perimeter of semicircular park = 1/2π*d
360 = 1/2*22/7*d
d = (360*14)/22
Diameter = 229 m
So, radius = 229/2 = 114.5 m

Area of semicircular park = πr²*1/2
= 22/7*114.5*114.5*1/2
= 20601.82 sq m
Answer.

Answer 2

Answer:

20616.21 sq.m

Step-by-step explanation:perimeter of semicircle = 22/7*r

                                                                             360*7/22 = r

                                                                              114.54 m = r

                                    area of semi circular park = 1/2*22/7*114.54*114.54

                                                                                 =20616.21 sq.m