find area of the following quadrilateral.
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Answer:
24.5 cm
Step-by-step explanation:
Area of this quadrilateral = sum of the areas of the inner triangles
so,
Δ ADC = (3 x 4) ÷ 2 = 12 ÷ 2 = 6cm²
Δ BHC = (7 x 5) ÷ 2 = 35 ÷ 2 = 17.5 cm²
Δ AHB = (4 x 5) ÷ 2 = 20 ÷ 2 = 10 cm²
Now,
area of quadrilateral = 6 + 17.5 + 10 (cm)
= 23.5 + 10
= 24.5 cm²
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