Question

find area of this quadrilateral

Answer 1

Answer:

Area of this parallelogram=2*(1/2*2*8)

=2*8=16 cm sq.

Answer 2

$\huge\red { Step\ by\ step\ explanation }$

As we can see there are two different triangles formed

Area of first triangle

= √s(s-a)(s-b)(s-c) [where {s = (a+b+c)/2} and a,b,c are sides of triangle]

= √8.5(8.5-4)(8.5-5)(8.5-8)

= √8.5(4.5)(3.5)(0.5)

= 8.18cm^2

as we know that both triangles are same

then,

area of quadrilateral

= 8.18+8.18

= 16.36cm^2

$\huge\red { Second\ step }$

If you mean the line drawn of 2cm is perpendicular to the line of 8cm

then also 2 triangles are formed

Area of first triangle

= 1/2(base×altitude)

= 1/2(8*2)

= 8cm^2

As we know that both triangles sides are equal then their perpendicular and area are also equal

then,

Area of quadrilateral

= 8+8

= 16cm^2


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$\huge\red { ... I\ hope\ it\ will\ help\ you }$
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