Question

find area of this triangle?

Answer 1

Here is your answer.....

Answer 2

Question:

To Find the area of the triangle

Given:

In ΔABC,

• AB = 12cm

• BM = 6.5 cm

To Find:

The area of the triangle

Formula Used:

$\sqrt{s(s-a)(s-b)(s-c)}\\\\\\\textsf{Where, is the semi perimeter}$

Solution:

$\textsf{In }\triangle ABC\\\\\\AC=(BM=AM)+(BM+MC)\\\\\\AB=12,AC=6.5+6.5=13\\\\\\(13)^2=(12)^2+(BC)^2\\\\\\169=144+(BC)^2\\\\\\169-144=(BC)^2\\\\\\25=(BC)^2\\\\\\(BC)^2=25\\\\\\BC=\sqrt{25}\\\\\\BC=5cm$

$Area=\sqrt{s(s-a)(s-b)(s-c)} \\\\\\s=semi-perimeter\\\\\\s=\frac{a+b+c}{2}\\\\\\Area=\sqrt{s(s-a)(s-b)(s-c)} \\\\\\s=\frac{12+13+5}{2}\\\\\\s=\frac{30}{2}\\\\\\s=15cm$

$\sqrt{15(15-12)(15-13)(15-5)}\\\\\\\sqrt{15(3)(2)(10)}\\\\\\\sqrt{5\times3\times3\times2\times2\times5}\\\\\\\sqrt{2^2\times3^2\times5^2}\\\\\\\sqrt{2^2} \times\sqrt{3^2} \times\sqrt{5^2} \\\\\\2\times3\times5\\\\\\=30cm\\\\\\\boxed{=30cm}$

Answer:

Area of the triangle = 30 cm