Find area of traingle ABC in which angle ABC=90 and angle ACB=45 and AC=6cm
raza808:
according to tenth standard textbook area of triangle =1%2×base×height but in question only one side given
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by Pythagorean theorem:
x^2+x^2=6^2
2x^2=36
x^2=18cm
area of right angles and isosceles triangle is:
=x^2/2
=18/2
=6cm
x^2+x^2=6^2
2x^2=36
x^2=18cm
area of right angles and isosceles triangle is:
=x^2/2
=18/2
=6cm
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