find area of triangle
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HEY_____MATE
YOUR ANSWER
Perimeter of that triangle = 60cm
the measure of hypotaneous = 25cm
then the rest sides must measure = 60-25
= 35
let one side be x
then, thw measure of the third side must be 35 - x
using pythagoras theorem
(25)^2 =(x)^2 + (35-x)^2
625 = x^2 + x^2 - 70x + 1225
x^2 + x^2 - 70x + 1225 = 625
x^2 + x^2 - 70x + 1225 -625 = 0
2 x^2 - 70x + 600 = 0
2x^2 - 40x - 30 x + 600= 0
2x (x-20) -30 ( x - 20) = 0
(x-20)(2x-30)=0
x -20 = 0
x = 20
2x -30 =0
2x =30
x = 15
so,
one of the side measure either 20 cm 15 cm
if one side measure 20cm then the other must measure 35 -20 = 15cm
and if it measured 15 cm then the other side measure 35-15 = 20 cm
so,
we will get 20cm and 15 cm as our remaining sides.
one of then will be height and the other misy be the base,
now apply the formula of area of triangle i.e
(1/2) (height)(base)
= (1/2 )(20)(15)
= 150 cm^2
so, the area of that triangle will be 150 cm^2.
YOUR ANSWER
Perimeter of that triangle = 60cm
the measure of hypotaneous = 25cm
then the rest sides must measure = 60-25
= 35
let one side be x
then, thw measure of the third side must be 35 - x
using pythagoras theorem
(25)^2 =(x)^2 + (35-x)^2
625 = x^2 + x^2 - 70x + 1225
x^2 + x^2 - 70x + 1225 = 625
x^2 + x^2 - 70x + 1225 -625 = 0
2 x^2 - 70x + 600 = 0
2x^2 - 40x - 30 x + 600= 0
2x (x-20) -30 ( x - 20) = 0
(x-20)(2x-30)=0
x -20 = 0
x = 20
2x -30 =0
2x =30
x = 15
so,
one of the side measure either 20 cm 15 cm
if one side measure 20cm then the other must measure 35 -20 = 15cm
and if it measured 15 cm then the other side measure 35-15 = 20 cm
so,
we will get 20cm and 15 cm as our remaining sides.
one of then will be height and the other misy be the base,
now apply the formula of area of triangle i.e
(1/2) (height)(base)
= (1/2 )(20)(15)
= 150 cm^2
so, the area of that triangle will be 150 cm^2.
saurabhbisht12:
it is correct
Answered by
13
Hey mate !!
Hypotenuse given 25cm
Perimeter = 60
Perimeter = sum of sides
=> base + perpendicular + 25 = 60
=> base + perpendicular = 60 - 25
=> base + perpendicular = 35cm
We know that, by Pythagoras theorem
Hypotenuse² = (base² + perpendicular²)
=> (b² + p²) = 25²
=> b² + p² = 625
Also we know that, using identity,
b² + p² = (b + p)² - 2bp
and base + perpendicular = 35 as derived above
=> 625 = (35)² - 2bp
=> 625 = 1225 - 2bp
=> -2bp = 625 - 1225
=> - 2bp = -600
=> bp = 600/2
=> base × perpendicular = 300
Now we know that area of triangle =
1/2 × base × perpendicular (height)
=> 1/2 × 300
=> 150cm²
Your answer 150cm²
Hope it helps dear friend ☺️✌️✌️
Nice question
Hypotenuse given 25cm
Perimeter = 60
Perimeter = sum of sides
=> base + perpendicular + 25 = 60
=> base + perpendicular = 60 - 25
=> base + perpendicular = 35cm
We know that, by Pythagoras theorem
Hypotenuse² = (base² + perpendicular²)
=> (b² + p²) = 25²
=> b² + p² = 625
Also we know that, using identity,
b² + p² = (b + p)² - 2bp
and base + perpendicular = 35 as derived above
=> 625 = (35)² - 2bp
=> 625 = 1225 - 2bp
=> -2bp = 625 - 1225
=> - 2bp = -600
=> bp = 600/2
=> base × perpendicular = 300
Now we know that area of triangle =
1/2 × base × perpendicular (height)
=> 1/2 × 300
=> 150cm²
Your answer 150cm²
Hope it helps dear friend ☺️✌️✌️
Nice question
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