Find area of triangle abc if angle a = 60 angle b = 30 ac=4
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For this problem you may apply the law of cosines,which is an extension of Pythagoras's Theorem. If ABC is our triangle, then:
BC^2 = AB^2 + AC^2 -[ 2*AB*AC*cos(A) ]
I used the right parantheses to avoid any confusion.
Thus we have:
BC^2 = 9 + 16 - [2*3*4*(1/2)]
BC^2 = 25 - 12
BC^2 = 13
BC = sqrt(13)
now you can find the area of triangle
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