find area of triangle ABC with A(1,-2) and mid points of sides pass through A being (2,-1),(0,-1)
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Answer:
The area of a triangle ABC is 4.
Step-by-step explanation:
We have to find the coordinates of the points B and C.
(xB + 1) / 2 = 2
xB + 1 = 4, xB = 3
(yB - 2)/ 2 = - 1
yB - 2 = - 2, yB = 0
(xC + 1 ) / 2 = 0
xC + 1 = 0, xC = - 1
(yC - 2) /2 = - 1
yC - 2 = - 2, yC = 0
Therefore : A ( 1, - 2 ) B ( 3, 0 ) C ( - 1, 0 ). The base BC = 4, h = 2.
The area : A = BC * h / 2 = 4 * 2 / 2 = 4
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