find area of triangle which has two sides is 8 cm and one side is 11 cm and perimeter is 32cm plz answer tomorrow is my online exam by heron's formula class 9
Answers
Answer:
let the sides of the triangle be a, b and c
given length of the sides of the triangle are :-
a = 8cm
b = 11cm
c = ?
perimeter of the triangle is given = 32cm
since the sum of all three sides of a triangle is it's perimeter
=> a + b + c = 32cm
=> 8 + 11 + c = 32cm
=> 19 + c = 32cm
=> c = 32 - 19
=> c = 13cm
now we will find the area of the triangle by heron's formula which is √s(s-a)(s-b)(s-c) where s is the semi-perimeter of the triangle.
semi-perimeter of this triangle = 32/2
= 16cm
area of the triangle = √16(16-8)(16-11)(16-13)
= √(16 × 8 × 5 × 3)
= √(2 × 2 × 2 × 2 × 2 × 2 × 2 × 5 × 3)
= 2 × 2 × 2√(2 × 5 × 3)
= 8√30cm²
HOPE THIS HELPS YOU!!
PLZZ MARK AS BRAINLIEST
Answer:
Let x be the unknown side..
Sides = 8cm, 11cm, x cm
Perimeter = 32cm
So third side = 32cm - (11cm+8cm)
= 32cm - 19 cm
= 13cm
Heron's Formula = √s(s-a) (s-b) (s-c)
Value is 's'(semi-perimeter)in heron's formula = (11+8+13)/(2)
= 16
Further steps are with attachments...
Hence the answer is 8√30 cm^2...
Hope this helps....
