Question

find area of triangle whose sides are 20cm,21cm and 29 cm and find its altitude corresponding to its longest side​

Answer 1

$\huge\mathbb\green{ANSWER}$

Sides → 20 cm, 21 cm, 29 cm...

Then, Here we have to use heron's formula....

Area →

$\pink{s(s - a)(s - b)(s - c)}$

Where, a , b, c are the sides of Triangle....

Then, We have to find →

s → a + b + c / 2

s → 20 + 21 + 29 / 2

s → 70 / 2

s → 35

•°• Area of Triangle

= √35(35-20)(35-21)(35-29)

= √35×15×14×6

= √44100

= 210

Answer → $\green{210}$

Hope it helps....(◕ᴗ◕✿)

Please mark me as a brainlist....