Question

Find area of triangle whose sides are 3cm, 4cm and 4cm.( There is no height)

Answer 1

Here, a= 3cm, b= 4cm and c= 4cm
then, perimeter ( s) = a+b+c/2
=3+4+4/2
=11/2
Now, by Heron's formula, we have
area of a triangle =
$\sqrt{(s - a)(s - b)(s - c)s}$
so, area of the triangle=
$\sqrt{5.5(5.5 - 3)(5.5 - 4)(55 - 4)}$
$\sqrt{5.5 \times 2.5 \times 1.5 \times 1.5}$
$\sqrt{2.25 \times \: 13.75}$
$\sqrt{30.9375 }$
=5.56 cm sq. (approx)