Question

find area of triangle whose vertices are (-4, 0) (4, 0) (0, 5)
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Answer 1

Answer:

16 is the answer.

Step-by-step:

[−4(4−0)+2(0−0)+4(1−4)]=∣−16∣

Since it is an area we take the positive value only.

∴arΔABC=16squnits.