find average of 1 integer 1 upon 2 , 2 integer 1 upon 3 , 3 integer 1 upon 3 , & 4 integer 5 upon 6
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Answer:
After one value is removed:
Since all of the values are Integers, the sum here must be an integer.
Sum=(number)×(average).
Since the average =35
17
7
, and the sum must be an integer, the number of integers must be a multiple of 17.
For any evenly spaced set, average = median.
After one of the consecutive integers is removed, most of the remaining set will still be evenly spaced.
As a result, the average of the remaining set 37
17
7
will still be close to the median.
Implication:
The number of integers =4×17=68, with the result that 35
17
7
will be close to the median of the 68 mostly consecutive integers.
∴ Sum=68×35
17
7
=2408.
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