the value of 1 upon 3 + 1 upon 3 X 1 upon 3÷1 upon 3 + 1 upon 3
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0
Step-by-step explanation:
Correct option is
C
27x
3
+
27x
3
1
=488
3x+
3x
1
=8
Squaring both sides,
=>(3x+(
3x
1
)
2
=8
2
=>(3x)
2
+(
3x
1
)
2
+2(3x)(
3x
1
)=64
=>(3x)
2
+(
3x
1
)
2
+2=64
=>(3x)
2
+(
3x
1
)
2
=64−2
=>(3x)
2
+(
3x
1
)
2
=62
Now,
=(3x)
3
+
3
3
1
=(3x+
3x
1
)[(3x
2
)−(3x)(
3x
1
)+(
3x
2
1
)]
=>27x
3
+
27x
3
1
=8(62−1)
=8(61)
=488
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