Find |AXB|
If, |A|=10 , |B|=2, and vector A.B=12
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Step-by-step explanation:
ANSWER ::
We know that
|A×B| ² + | A.B |² = |A |² | B |²
So
|A×B| ² + | 12 |² = 10² × 2²
|A×B| ² = 400 - 144
|A×B| ² = 256
|A×B| = 16
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