Question

find b
$\implies\sf \: Θ = \frac{12}{5}$
find the value of
$\implies\sf \: \frac{1 + \sin Θ }{1 - \sin Θ }$

please solve it ​

Answer 1

Answer:

25

Step-by-step explanation:

=1+sini/1-sini

=1+12/13/1-12/13

=25

Answer 2

Answer:

$\huge{\underline{\bf{\red{Solution:-}}}}$

we have ,

$\implies\sf \ \: \tan Θ = \frac{12}{5}$

$\implies\sf \: ∴ \: \sinΘ = \sqrt{1 + { \tan }^{2} Θ} = \sqrt{1} + ( \frac{12}{5 } ) {}^{2} = \sqrt{ \frac{169}{25} = } \frac{13}{5}$

$\implies\sf \:∴ \ \cosΘ = \frac{1}{ { \sec Θ }^{} } = \frac{5}{13}$

$\small{\underline{\bf{\green{NOW,}}}}$

$\sinΘ = \sqrt{1 - { \cos }^{2} Θ } \implies \sinΘ = \sqrt{1 - ( \frac{5}{13}) {}^{2} } = \sqrt{ \frac{144}{169} } = \frac{12}{13}$

$\large{\underline{\bf{\pink{Thus}}}},$

$\implies\sf \: \frac{1 + \sin Θ }{1 - \sin Θ } = \frac{1 + \frac{12}{13} }{1 - \frac{12}{13} } = \frac{ \frac{25}{13} }{ \frac{1}{13} } = 25$

$\large{\underline{\bf{\green{HENCE \: \: PROVED }}}}$