find by newton's method the root of the equation x³-3x+1=0 which is between 1 and 2
Answers
Answered by
2
Answer:
I know here f '(1) =0. I found in some texts if f ' (x) = 0 for some x then we can't apply N-R method. Is there any other technique to find first approximation for x^3-3x+1 = 0 taking initial approximation as 1
Step-by-step explanation:
mark me as brainlist
Similar questions