Math, asked by eesh17, 2 months ago

find by newton's method the root of the equation x³-3x+1=0 which is between 1 and 2​

Answers

Answered by ruba5367
2

Answer:

I know here f '(1) =0. I found in some texts if f ' (x) = 0 for some x then we can't apply N-R method. Is there any other technique to find first approximation for x^3-3x+1 = 0 taking initial approximation as 1

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