Math, asked by vicky269i, 1 year ago

find C.I. on 6500 at 10% for 2 years compounded annually

Answers

Answered by vanshikaaax
0
P = 6500
R = 10%
T = 2 years
A = p( 1+r/100)power T
A = 6500( 1 +10/100)power 2
A= 6500 ( 11/10 11/10)
A = xyz
And the
Ci = A - P = Ci! ❤️ I hope the answer was helpful to you If it was please mark it as brainlist ❤️
Answered by QUEEN007
2
Hey Friend ☺

Given

Principal ( P ) = Rs 6500

Rate of interest ( R ) = 10% p.a.

No. of years ( N ) = 2

To Find

Compound interest = ?

Solution

First we have to find Amount ( A )

A = P ( 1 + R/100 )^N

= 6500 ( 1 + 10/100 )^2

= 6500 ( 11/10 )^2

= 6500 × 11/10 × 11/10

= 65 × 11 × 11

= 65 × 121

= 7856

So amount is Rs 7856

C.I. = A - P

= 7856 - 6500

= 1356

so the compound interest is Rs 1356

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