find C.I. on 6500 at 10% for 2 years compounded annually
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Answered by
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P = 6500
R = 10%
T = 2 years
A = p( 1+r/100)power T
A = 6500( 1 +10/100)power 2
A= 6500 ( 11/10 11/10)
A = xyz
And the
Ci = A - P = Ci! ❤️ I hope the answer was helpful to you If it was please mark it as brainlist ❤️
R = 10%
T = 2 years
A = p( 1+r/100)power T
A = 6500( 1 +10/100)power 2
A= 6500 ( 11/10 11/10)
A = xyz
And the
Ci = A - P = Ci! ❤️ I hope the answer was helpful to you If it was please mark it as brainlist ❤️
Answered by
2
Hey Friend ☺
Given
Principal ( P ) = Rs 6500
Rate of interest ( R ) = 10% p.a.
No. of years ( N ) = 2
To Find
Compound interest = ?
Solution
First we have to find Amount ( A )
A = P ( 1 + R/100 )^N
= 6500 ( 1 + 10/100 )^2
= 6500 ( 11/10 )^2
= 6500 × 11/10 × 11/10
= 65 × 11 × 11
= 65 × 121
= 7856
So amount is Rs 7856
C.I. = A - P
= 7856 - 6500
= 1356
so the compound interest is Rs 1356
✌
Given
Principal ( P ) = Rs 6500
Rate of interest ( R ) = 10% p.a.
No. of years ( N ) = 2
To Find
Compound interest = ?
Solution
First we have to find Amount ( A )
A = P ( 1 + R/100 )^N
= 6500 ( 1 + 10/100 )^2
= 6500 ( 11/10 )^2
= 6500 × 11/10 × 11/10
= 65 × 11 × 11
= 65 × 121
= 7856
So amount is Rs 7856
C.I. = A - P
= 7856 - 6500
= 1356
so the compound interest is Rs 1356
✌
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