Find c,if 2 raised power a=3 raised power b=6 raised power c?
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a=c log(2)6
=>c=a/log(2)6
2^a=6^c
=>2^a=(2^c)(3^c)
=>2^a-c=3^c
now,
3^b=(3^c)(2^c)
=>2^c=3^b-c
=>c=(b-c)log(2)3
=>a/log(2)6=(b-c)log(2)3
=>a=(b-c)log(2)9
and, 2^a=3^b
=>a=b log(2)3
=>b=a/log(2)3
RHS= ab/a+b
=b² log(2)3/b(1+log(2)3)
=b log(2)3-6
=a/log(2)6
=c
=RHS [showed]
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