Question

Find 'c' if the roots of quadratic equation are real and equal
x ²- 2 (c + 1 ) x + c²=0​

Answer 1

Answer:

c equal to 0 as i know ....

Answer 2

Step-by-step explanation:

Given quadratic equation is x² - 2(c + 1)x + c² = 0

Also said that the roots of the quadratic equation are real and equal.

We have to find the value of c.

Quadratic formula:

x = -b ± √(b² - 4ac)/2a

OR

x = - b ± √D/2a

D = b² - 4ac

As the roots of the quadratic equation are real and equal. So, "D" must be equal to zero.

→ D = b² - 4ac = 0

→ [-2(c + 1)]² - 4(1)(c²) = 0

→ 4(c² + 1 + 2c) - 4c² = 0

→ 4c² + 4 + 8c - 4c² = 0

→ 8c = -4

→ c = -4/8

→ c = -1/2

Hence, the value of c is -1/2.