find centre of mass of a right angled triangle
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For a right triangle, the centroid can be located as follows. From the right angle, measure one-third of the distance along the two adjacent sides to the other vertices. Draw lines at right angles to the sides at the one-third points, and the intersection of the lines should be the centroid.
More generally for any triangle, with vertices L, M and N, which have co-ordinates (xL, yL), (xM, yM) and (xN, yN), respectively, the centroid should be located at the point:
(1/3(xL + xM + xN), 1/3(yL + yM + yN))
Getting the centroid of triangles using the more general formula for a closed polygon doesn’t seem to work, but the above methods should.
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For a right triangle, the centroid can be located as follows. From the right angle, measure one-third of the distance along the two adjacent sides to the other vertices. Draw lines at right angles to the sides at the one-third points, and the intersection of the lines should be the centroid.
More generally for any triangle, with vertices L, M and N, which have co-ordinates (xL, yL), (xM, yM) and (xN, yN), respectively, the centroid should be located at the point:
(1/3(xL + xM + xN), 1/3(yL + yM + yN))
Getting the centroid of triangles using the more general formula for a closed polygon doesn’t seem to work, but the above methods should .
HOPE , IT HELPS ..
For a right triangle, the centroid can be located as follows. From the right angle, measure one-third of the distance along the two adjacent sides to the other vertices. Draw lines at right angles to the sides at the one-third points, and the intersection of the lines should be the centroid.
More generally for any triangle, with vertices L, M and N, which have co-ordinates (xL, yL), (xM, yM) and (xN, yN), respectively, the centroid should be located at the point:
(1/3(xL + xM + xN), 1/3(yL + yM + yN))
Getting the centroid of triangles using the more general formula for a closed polygon doesn’t seem to work, but the above methods should .
HOPE , IT HELPS ..
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