Question

The first line in the lyman series has wavelength λ. the wavelength of the first line in balmer series is

Answer 1

for lyman series n=1 wavelength is given which is lambda

For balmer series n=2

As wavelength is directly proportional to square of 'n' so, let us assume wavelength of Balmer series to be equal to 'x'

Lambda/x = 1×1/2×2

4(lambda) = x

So, wavelength of balmer series is 4 times of lambda which is wavelength of lyman series