Question

find centroid of triangle of abc a (3-1) b (10,7) and c (5,3)

Answer 1

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Coordinates of centroid of ∆ =>

$( \frac{x1 + x2 + x3}{3} , \: \frac{y1 + y2 + y3}{3} )$

So,

$\frac{3 + 10 + 5}{3} , \frac{ - 1 + 7 + 3}{3}$

$(\frac{18}{3} , \frac{9}{3} )$

$= > \boxed{ \boxed{\: (6,3)}}$

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Answer 2

given vertices a= 3,-1
b = 10,7
c=5,3 .

centriod G = x1+x2+x3/3
y1 +y2+ y3

3+10+5/3 , -1+7+3 /3

18/3 , 9/3
6,3





centriod is 6,3