Question

Find compound interest of 5000₹ at. 5p.c.p.a. for 3 years

​

Answer 1

Answer:

Rs. (11025 – 10000) = Rs. 1025

Step-by-step explanation:

Mental and paperwork! sorry!

Answer 2

AnswEr:

GivEn:

• Principal value (P) = ₹ 5000
• Time (t) = 3 years
• Rate (r) = 5 %

To Find:

• Amount of the Transactions ?

Solution:

Formula Used:

$\\ \huge\red{\boxed{\sf{ A = P [ (1+ \dfrac{R}{100} )^T ] }}}$

$\implies{\sf{ 5000[(1+ \dfrac{5}{100} )^3 ] }} \\ \\ \implies{\sf{ 5000[( \dfrac{21}{20} )^3 ] }} \\ \\ \implies{\sf{ \dfrac{5 \cancel{000} \times 9261}{ 8 \cancel{000}} }} \\ \\ \implies{\sf{ \dfrac{5 \times 9261}{8} }} \\ \\ \implies{\sf{ \dfrac{ \cancel{46305}^ { \: \: 5788.125}}{ \cancel{8}} }} \\ \\ \implies\blue{\sf\bf{ Rs. \: \: 5788.125 }}$

━━━━━━━━━━━━━━━━━━━━━━━━━

CI = Amount - Principal Value

$\implies\sf\bf { 5788.125 - 5000} \\ \\ \implies\sf\bf\underbrace\orange{ \: \: Rs. \: \: 788.125 \: \: }$

━━━━━━━━━━━━━━━━━━━━━━━━━

Hence,

The Compound Interest is ₹ 788. 125