Question

find compound interest on 24000 at 15 % per annum for 2 years compounded annually​

Answer 1

PLEASE MARK AS BRAINLYEST

Principal=P=24,000

Rate of interest=r=15%

Time=n=2

3

1

years

Here first we take n=2years

A=P(1+

100

r

)

n

where A=Amount and n=number of years

A=24000(1+

100

15

)

2

=24000×

100

115

×

100

115

=Rs.$$31,740‬$$

The amount after 2 years is Rs$$31,740‬$$

Now principal=Rs.$$31,740‬$$

Simple interest for last

3

1

year is $$\dfrac{PRT}{100}=31,740‬\times \dfrac{15}{100}\times \dfrac{1}{3}=$$ Rs.$$1,587‬$$

∴ Amount after 2

3

1

year= Rs.31740+1587= Rs.33,327

C.I =A−P

∴C.I=33,327−24,000=Rs.$$9,327‬$$

∴ the compound interest is Rs.$$9,327‬$$

Answer 2

P = ( 1 + r/100 ) n

24000( 1 + 15/100 ) 2
24000 x 115/100 x115/100
24 x 115/10 x 115
115x115 = 13,225/10
1,322.5 x 24
= 31,980
C.I = 31,980 - 24000
= 7,980

This is what I am getting