Question

find compound interest on a sum of rupees 8000 for 2 years at 5% per annum compounded annually​

Answer 1

Answer:

: hope it helps you

Answer 2

Given :

• Principal = Rs.8000
• Rate of ineterst = 5%
• Time = 2 years

To Find :

• The compound interst

Solution :

Compound interest is given by ,

$\\ \star \: {\boxed{\purple{\sf{ CI= P\bigg[ \bigg( 1 + \frac{R}{100} \bigg)^{t} - 1} \bigg]}}}$

$\\ : \implies \sf \:CI = 800 \bigg[ \bigg(1 + \frac{5}{100} \bigg)^{2} - 1 \bigg ]$

Here ,

• P is principal
• R is Rate of interest
• t is time

Substituting the values ,

$\\ : \implies \sf \:CI = 8000 \bigg[ \bigg(1 + \frac{5}{100} \bigg)^{2} - 1 \bigg ]$

$\\ : \implies \sf \: CI = 8000 \bigg[ \bigg( \frac{100 + 5}{100} \bigg) ^{2} - 1\bigg]$

$\\ : \implies \sf \: CI = 8000 \bigg[ \bigg( \frac{105}{100} \bigg)^{2} - 1\bigg]$

$\\ : \implies \sf \: CI = 8000 \bigg[ \bigg( \frac{105 \times 105}{100 \times 100} \bigg) - 1\bigg]$

$\\ : \implies \sf \: CI = 8000 \bigg[ \bigg( \frac{11025}{10000} \bigg) - 1\bigg]$

$\\ : \implies \sf \: CI = 8000 \bigg[ \bigg( \frac{11025 - 10000}{10000} \bigg) \bigg]$

$\\ : \implies \sf \:CI = 8000 \bigg( \frac{1025}{10000}\bigg)$

$\\ : \implies \sf \:CI = \frac{8 \times 1025}{10}$

$\\ : \implies \sf \: CI = 8 \times 102.5$

$\\ : \implies{\underline{\boxed {\pink{\mathfrak{CI = Rs.820}}}}} \: \bigstar$

$\\ \therefore{\underline{\sf{Hence , \: The \: Compound \: Interest \: on \: given \: sum \: is \: \bold{Rs.820}}}}$