Question

find compound interest on Rs. 15000 fir 2 years at 10%p.a compounded annually​

Answer 1

Hence Compound Interest is = Rs. 3150.

●Refer the attachment now●

Answer 2

Answer :

➥ The compund Interest = 3150

Given :

➤ Principal (P) = Rs. 15000

➤ Rate (R) = 10 %

➤ Time (T) = 2 years

To Find :

➤ Compund Interest (C.I) = ?

Solution :

To find compund Interest first we need find amount then after we find compund Interest.

As we know that

$\tt{: \implies A = P \bigg( 1 + \dfrac{R}{100} \bigg)^n}$

$\tt{: \implies A = 15000\bigg( 1 + \dfrac{10}{100} \bigg)^2}$

$\tt{: \implies A = 15000\bigg(\dfrac{10}{100} \bigg)^2}$

$\tt{: \implies A = 150 \cancel{00} \times \dfrac{11 \cancel{0}}{1 \cancel{00}} \times \dfrac{11 \cancel{0}}{1 \cancel{0} \cancel{0}}}$

$\tt{: \implies A = 150 \times 11 \times 11}$

$\tt{: \implies A = 1650 \times 11}$

$\bf{: \implies \underline{ \: \: \underline{ \green{ \: \: A = Rs. \: 18450 \: \: }} \: \: }}$

Now ,

We find compund Interest.

As we know that

$\tt{: \implies C.I = A - P}$

$\tt{: \implies C.I = 18150 - 15000}$

$\bf{: \implies \underline{ \: \: \underline{ \purple{ \: \: C.I = 3150 \: \: }} \: \: }}$

Hence, the compund Interest is 3150.