Find compound interest on rs 8000 for 4 years at10% per year
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Hi ,
Principal = p = Rs 8000
Time = t = 4 years
number of times interest paid = n = 4
rate of interest = r = 10%
Let amount = A
A = p( 1 + r/100 )ⁿ
A = 8000[ 1 + 10/100 ]⁴
A = 8000 [ 1 + 1/10 ]⁴
A = 8000 × ( 11/10 )⁴
A = ( 8000 × 11 × 11 × 11 × 11 )/ 10000
A = 117128/10
A = Rs11712.80
compound interest = A - p
= Rs11712.80 - Rs 8000
= Rs 3712.80
I hope this helps you.
: )
Principal = p = Rs 8000
Time = t = 4 years
number of times interest paid = n = 4
rate of interest = r = 10%
Let amount = A
A = p( 1 + r/100 )ⁿ
A = 8000[ 1 + 10/100 ]⁴
A = 8000 [ 1 + 1/10 ]⁴
A = 8000 × ( 11/10 )⁴
A = ( 8000 × 11 × 11 × 11 × 11 )/ 10000
A = 117128/10
A = Rs11712.80
compound interest = A - p
= Rs11712.80 - Rs 8000
= Rs 3712.80
I hope this helps you.
: )
Answered by
0
Amount=principle(1+rate of interest/100)^no .of years
=8000(1+10/100)^4
=8000×11/10×11/10×11/10×11/10
=58564/5
=11,712.8
Compound interest=Amount-principle
=11,712.8-8000
=3712.8 R's.
HOPE IT HELP!!
=8000(1+10/100)^4
=8000×11/10×11/10×11/10×11/10
=58564/5
=11,712.8
Compound interest=Amount-principle
=11,712.8-8000
=3712.8 R's.
HOPE IT HELP!!
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