Question

find compound interest on rupees 20000 for 4 years at 5% p a​

Answer 1

Answer:

ANSWER IN THE ATTACHMENT ⤴️

Step-by-step explanation:

I HOPE THIS WILL BE CORRECT AND IT WILL HELP YOU ✨⚡

Answer 2

Given: Principal (P) = Rs. 20,000

           Time (n) = 4 years

           Rate of interest (R) = 5 % p.a

To find: Compound Interest

Solution: Calculating the amount after 4 years,

∵ $Amount = P(1 \ + \ \frac{R}{100} )^{n}$

⇒ $20,000 ( 1 \ + \ \frac{5}{100}) ^{4}$

⇒ $20,000 * (\frac{21}{20})^{4}$

⇒ $20,000 * \frac{21}{20}* \frac{21}{20} *\frac{21}{20}* \frac{21}{20}$

⇒ 24,310.125

Amount after 4 years = Rs. 24,310.125

∵ $Interest = Amount - Principal$

⇒ 24,310.125 - 20,000

⇒ Rs. 4,310.125

Hence, compound interest on Rs. 20,000 for 4 years at 5% p.a. is Rs. 4,310.125.