Question

find compound interest rupees 12600 for 2years at 10% per annum compounded annually

Answer 1

$\bold{\underline{Hey\: Mate !}}$

$\underline{Given\: \colon}$

P = 12600

n = 2 years (time)

r = 10 %

$\underline{ To\: Find\: \colon}$

Compound interest = ?

$\underline{Solution \: \colon}$

$A \: = \: P(1\: + \: \frac{r}{100})^{n}\\\\\implies A \: = \: 12600(1\: + \: \frac{10}{100})^{2} \\\\ \implies 12600(\frac{10+1}{10})^{2} \\\\\implies 12600(1.1)^{2} \\\\\implies 12600\times 1.1\times 1.1 \\\\\implies 15246$

Total amount = 15246

C.I. = 15246 - 12600

C.I. = ₹ 2,646

$\bold{\underline{Answer}}$

$\bold{\boxed{ C.I. \: = \: Rs \:2,646}}$

Answer 2

$\huge\bf{Answer:-}$

Refer the attachment.