Question

find compound intrest and amount of p=10000 for 2years at 11% rate of interest

Answer 1

${p(1 + \frac{r}{100} )}^{n} \\ = 10000 {(1 + \frac{11}{100} )}^{2} \\ = 10000 \times \frac{111}{100} \times \frac{111}{100} \\ = 111 \times 111 \\ = 12321 \\ \\ 12321 \: is \: the \: answer$