Math, asked by Aki456, 1 year ago

Find condition which must be satisfied by coefficient of polynomial xcube-px square+qr-r when sum of its 2 zero iszero

Answers

Answered by raji2112
128

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Answered by mysticd
61

Answer:

Required condition:

Required condition:pq = r

Step-by-step explanation:

Let p(x) = x³-px²+qx-r,

\alpha,\beta\: and \:\gamma\\ are \: three \: zeroes \:of \: p(x)

\alpha+ \beta = 0 ---(1)\*given*\

Compare p(x) with ax³+bx²+cx+d , we get

a=1 , b=-p,c=q,d=-r

Now,

i) \alpha+\beta+\gamma=\frac{-b}{a}

\implies 0+\gamma=\frac{-(-p)}{1}

\* From (1)*\

\implies \gamma = p--(2)

ii)\alpha\beta+\beta\gamma+\gamma\alpha=\frac{c}{a}

\alpha\beta+\gamma(\alpha+(\beta)=\frac{c}{a}

\implies \alpha\beta+\gamma \times 0=\frac{q}{1}

\implies \alpha\beta=q--(3)

 iii) \alpha\beta\gamma=\frac{-d}{a}

 \implies  (\alpha\beta)\gamma=\frac{-(-r)}{1}

\implies q\times p = r

/* From (2) and (3)

\implies pq = r

Therefore,.

Required condition:

pq = r

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