Question

Find coordinates of the centre of the circle X square + Y square - 4 x + 6 Y equal to 3. Given that the point A outside the circle has coordinates a b where A and B are both positive and that the tangents drawn from a to the circle are parallel to the two Axis respectively find the values of a and b

Answer 1

Answer:

The coordinates of point A ( a, b) will be ( 6, 1)

Step-by-step explanation:

$x^{2} + y^{2} - 4x + 6y = 3$

$\Rightarrow x^2 - 4x + 4 + y^2 + 6y + 9 -13 = 3$

$(x-2)^{2} + ( y + 3)^2 = 16$

Center of the circle = (2,-3) and radius  = 4.

The coordinates of point A ( a, b) will be ( 6, 1)