Question

find cosec 30° and cos 60° geometrically. plz do fast urgent​

Answer 1

Cosec 30 = 2

Cos 60 = $\sqrt{3}$ / 2

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Answer 2

Answer:

Step-by-step explanation:

Let there be equilateral triangle ABC.

Let AB = BC = AC = 2 a

Let AD be perpendicular on BC . So BD = DC

By pythogaras therom, AD = √3 a

and ∠BAC = 60° and ∠BAD = 30°.

So In Δ ABD,

Let ∠BAD be Ф

So cosec Ф = hypotenuse / height = 2 a/ a

cosec 30° = 2

In Δ ABD ,

Ф = ∠ ABD

COS Ф = base / hypotenuse.

cos 60° = BD / AB

=  a / 2 a

cos 60° = 1/2