find cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively, the perpendicular distance between them is 15 cm and the rate of watering is rupees 4 per metre square..notice that h is in cm..
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Given the parallel sides as 10 m & 25 m.
=1000 cm & 2500 cm
And the distance between them = 15 cm
So the area of the trapezium = ½ × 15 ×(1000+2500) cm²
= ½ × 15 ×3500 cm²
= 15 × 1750 cm²
= 26250 cm²
=2.625 m²
₹4 costs per 1 square metre watering.
So 2.625 square metre will cost = ₹2.625 × 4
= ₹ 10.5
That's it
Hope it helped (｡>﹏<｡)
=1000 cm & 2500 cm
And the distance between them = 15 cm
So the area of the trapezium = ½ × 15 ×(1000+2500) cm²
= ½ × 15 ×3500 cm²
= 15 × 1750 cm²
= 26250 cm²
=2.625 m²
₹4 costs per 1 square metre watering.
So 2.625 square metre will cost = ₹2.625 × 4
= ₹ 10.5
That's it
Hope it helped (｡>﹏<｡)
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But you should have gave me some time to correct it.
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But now I'm giving you the answer ₹4 × 2.625 = ₹10.5
Hope you will satisfy now with my answer.
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