Math, asked by ramtekedhanashree1, 6 months ago

find critical point of curve y= x³-3x+11​

Answers

Answered by suhasinipandraju
0

Answer:

(1,9)

Step-by-step explanation:

Derivative of y is

dy/dx=3x-3

to find critical points

dy/dx=0

 3x-3=0

3x=3

   x=1

and when x=1  

then    y=1-3+11=9

hence the critical points=(1,9)

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