find critical point of curve y= x³-3x+11
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Answer:
(1,9)
Step-by-step explanation:
Derivative of y is
dy/dx=3x-3
to find critical points
dy/dx=0
3x-3=0
3x=3
x=1
and when x=1
then y=1-3+11=9
hence the critical points=(1,9)
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