Question

find critical point of x^3/2(2-x)
ans me please​

Answer 1

Answer:

To find the critical points you first take the derivative using the power:

d

d

x

=

x

n

=

n

x

n

−

1

The derivative of

f

(

x

)

=

x

3

−

2

x

2

+

3

x

is:

d

d

x

=

3

x

2

−

4

x

+

3

Now you set it equal to zero and solve:

3

x

2

−

4

x

+

3

=

0

When you solve it, it will yield complex roots:

x

=

1

3

(

2

−

i

√

5

)

and

x

=

1

3

(

2

+

i

√

5

)

These two solutions are your critical numbers

Step-by-step explanation:

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