Math, asked by ansariabuzar3662, 11 months ago

find cube of 101 by using identity a³+b³+3ab(a+b)

Answers

Answered by Manishnitrr2010

1

Answer:

100+1

100³+1³+3×100×1×(100+1)

ansariabuzar3662: yes

Manishnitrr2010: got it??

Answered by DrNykterstein

1

===> (101)³

===> (100 + 1)³

(a + b)³ = a³ + b³ + 3ab ( a + b)

===> 100³ + 1³ + 3×100×1 (100 + 1)

===> 1000000 + 1 + 300×101

===> 1000001 + 30300

===> 1030301

Answer to this question is 1030301

ansariabuzar3662: very nice

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