find cube root of 300763 by estimation
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Estimating Cube Root, this method will work only if the given number is a perfect cube. The following are the steps to estimate the cube root.
Step I : Make groups of 3 digits from unit(one's) place.This the 1st group.The remaining number makes the 2nd group.
Step II : The unit's digit of the 1st group will decide the unit digit of the cube root.( if the unit digit of the cube is 6 then the unit digit of cube root will also 6 as 6 x 6 x 6 = 36).
Step III : Find the cube of numbers between which the 2nd group lie.
Step IV : Take the smaller number as its ten's digit.
Unit digit of a given numberUnit digit of cube root11374455667382
Examples on estimating cube root :
1) Find the cube root of 238328.
Solution :
238328 is an even number so its cube root has to an even number.
Make two groups ---> 238 328
First group 328 ---> unit digit is 8 so unit digit of cube root will be 2.
(see the above table).
Second Group 238 -----> it lies between 63=216 and 73 =343 .
So take the smaller number 6 as ten's place.
∴ ∛238328 = 62 hope it will help you. I don't know exact answer but I know that it will help you.
Step I : Make groups of 3 digits from unit(one's) place.This the 1st group.The remaining number makes the 2nd group.
Step II : The unit's digit of the 1st group will decide the unit digit of the cube root.( if the unit digit of the cube is 6 then the unit digit of cube root will also 6 as 6 x 6 x 6 = 36).
Step III : Find the cube of numbers between which the 2nd group lie.
Step IV : Take the smaller number as its ten's digit.
Unit digit of a given numberUnit digit of cube root11374455667382
Examples on estimating cube root :
1) Find the cube root of 238328.
Solution :
238328 is an even number so its cube root has to an even number.
Make two groups ---> 238 328
First group 328 ---> unit digit is 8 so unit digit of cube root will be 2.
(see the above table).
Second Group 238 -----> it lies between 63=216 and 73 =343 .
So take the smaller number 6 as ten's place.
∴ ∛238328 = 62 hope it will help you. I don't know exact answer but I know that it will help you.
ramireddy2:
you are always welcome
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