Question

Find current in 10V cell?

Answer 1

Solution :

Current in 10V cell is 4V

Theory :

•KIRCHHOFF's LAW

1) First law :

In any electrical network , the algebraic sum of currents meeting at the junction is always zero.

$\sf\:\sum\:I=0$

2) Second law :

The algebraic sum of all the potential drops and EMF's along any closed path in a network is zero.

$\sf\:\sum\:V=0$

Explanatìon :

We have to find the current in 10V cell .

From the attachment:

In 10Ω resistor :

V=IR

10=I×10

I=1 A

Now in loop CDFE

On Applying, second law of Kirchhoff ( KVl )

Then ,

$\sf\:5i-10+5i=20$

$\sf\implies\:10i=30$

$\sf\implies\:i=3A...(1)$

Now at the point C

i+1=i'

i'=1+i [from (1) i=3A ]

i'=3A

Therefore,Current in 10V cell is 4V

Answer 2

To Find :- Current in 10 V cell.

Answer :- 4V .

Concept :-

• The above question is to be solved by kirchoffs law.

➪These laws are used in calculating the electrical resistance of a complex network.

1) First law :

The algebraic sum of currents meeting at the junction is always zero.

$\implies \sf\:\sum\:I=0$

2) Second law :

The algebraic sum of all the potential drops and EMF's along any closed path in a network is zero.

$\sf\:\sum\:V=0$

Solution :

In 10Ω resistor ,

» V=IR

=> 10=I×10

I=1 A

From loop CDFE,

Apply second law ,

$\sf\:5i-10+5i=20$

$\sf\implies\:10i=30$

$\sf\implies\:i=3A...(1)$

at point C,

=> i+1=i'

=> i'=1+i [ i=3A ]

=> i' = 3 + 1

$\boxed{\implies <strong><u>i'= 4V</u></strong>}$

Hence , Current in 10V cell is 4V.

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HOPE IT HELPS :)