Question

Find Current In 3 ohm resistance
Ans is - 5/7 Ampre
How To Solve This All Steps Plz ​

Answer 1

Answer:

The required current is $\frac{5}{7} A$.

Explanation:

Concept:

First Law of Kirchhoff or the Junction Rule Any junction in an electric circuit has an algebraic sum of electric currents equal to zero, indicating that the total amount of current going into and out of the junction is equal.

Given:

Resistance$=3$ ohm

To find:

We have to find the current.

Solution:

The voltage of ground is assumed to be $0V$,

Assume that the grounds be named as $1,2,3$ respectively,

Assume the current in $1$st $2$Ω be $i$, and the $3$Ω be $i_{1}$

Applying Kirchhoff Voltage law , from ground $1$ to ground $2$,

$0+10-2i-2((i-i_{1} )=0$

$2i-i_{1} =5 .......(1)$

Now applying Kirchhoff Voltage law from ground $1$ to ground $3$,

$0+10-2i-3i_{1} -3i_{1} =0$

$2i-6i_{1} =10 .......(2)$

Subtract equation $(1)$ from $(2)$,

$7i_{1} =5$

$i_{1} =\frac{5}{7}A$

The value of current is $\frac{5}{7} A$.

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Answer 2

Answer:

We know that the voltage of the ground is considered $0V$.

Let's give the grounds the numbers 1, 2, and 3 respectively.

Let the current in resistance 2Ω be $I$ and the current in resistance 3Ω to $I_{1}$

Applying Kirchoff Voltage Law from ground 1 to ground 2

$0+10-2I-2(I-I_{1} )=0$

$2I+I_{1}=5$   ......(1)

Applying Kirchoff Voltage Law from ground 1 to ground 3

$0+10-2I-3I_{1}-3I_{1}=0$

$2I+6I_{1}=10$    .......(2)

Subtracting equation (1) from (2), we get

$7I_{1}=5$

$I_{1} =\frac{5}{7}A$

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