Question

Find current in the circuit.

Answer 1

Hey dear here is your answer!!!!!

___________________________

Firstly, lets name the resistors and write down all the things given:-

Resistor 1 - Top Left

Resistor 2 - Top Right

Resistor 3 - Base of Triangle

Voltage = 2V

Resistor 1 and 2 are in series so they will add up:-

= 2 + 2 Ohms

= 4 Ohms

Now, let's call this sum of Resistor as A.

Now, Resistor A and Resistor 3 are in parallel so:-

$\frac{1}{Effective Resistance}$ = $\frac{1}{RA}$ + $\frac{1}{R3}$

$\frac{1}{Effective Resistance}$ = $\frac{1}{4}$ + $\frac{1}{2}$

$\frac{1}{Effective Resistance}$ = $\frac{3}{4}$

Effective Resistance = 4/3

Now, V=RI

2 = 4/3 * I

I = 2 * 3 /4

I =6/4

I = 3/2

I = 1.5 A

❣️⭐ Hope it helps u dear...⭐⭐❣️❣️

Answer 2

Hey dear here is your answer!!!!!

___________________________

Firstly, lets name the resistors and write down all the things given:-

Resistor 1 - Top Left

Resistor 2 - Top Right

Resistor 3 - Base of Triangle

Voltage = 2V

Resistor 1 and 2 are in series so they will add up:-

= 2 + 2 Ohms

= 4 Ohms

Now, let's call this sum of Resistor as A.

Now, Resistor A and Resistor 3 are in parallel so:-

$\frac{1}{Effective Resistance} </p><p></p><p> </p><p> = \frac{1}{RA} </p><p></p><p> </p><p> + \frac{1}{R3}$

$</p><p>\frac{1}{Effective Resistance} </p><p></p><p> </p><p> = \frac{1}{4} </p><p></p><p> </p><p> + \frac{1}{2}$

$\frac{1}{Effective Resistance} </p><p> </p><p> = \frac{3}{4}$

Now, V=RI

2 = 4/3 * I

I = 2 * 3 /4

I =6/4

I = 3/2

I = 1.5 A

❣️⭐ Hope it helps u dear...⭐⭐❣️❣️