Question

pleezzzzz I need it fast

Answer 1

theta in this case is 45°
now solve with the value

Answer 2

HeY !!

sin¢ = cos¢

then if we adding and squaring both

we know that [ sin²¢ + cos²¢ = 1 ]

but according to question both are same hence

sin²¢ + sin²¢ = 1

2sin²¢ = 1

sin²¢ = 1/2

sin¢ = √1/2 .

sin¢ = sin45°

¢ = 45°

NOW put out the value of ¢ on given

3tan²¢ + 2sin²¢ + cos²¢ - 1

3×tan²45° + 2sin²45° + cos²45° - 1

3 × (1/√2)² + 2 × ( 1/√2)² + (1/√2)² - 1

3 × 1/2 + 2 × 1/2 + 1/2 - 1

3/2 + 1 + 1/2 - 1

3 + 2 + 1 - 2/2

= 4/2 = 2 Answer


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Hope it helps you !!!..

@Rajukumar111