Question

find curved surface area of the frustum of a cone the diameter of a circular insert 20 metre and 6 metre and its height is 24​

Answer 1

Answer:

ans

answer is 485.714sqm

Answer 2

The curved surface area of the frustum of  cone is 325П m²

Diameter of the bigger circle of the cone = 20m

So, radius (r) = 20/2 = 10m

height (h) = 24m

Diameter of the smaller circle of the cone = 6m

So, radius (r') = 6/2 = 3m

Slant height (l) = √[(r-r')²+(h²)]

Substituting the values, we get:

l = √[7²+24²]

= 25m

So, curved surface area = П(r+r')l

= П(10+3)*25

= 325П m²