Find D + e + F from the following DEF ×d = 10 DF
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Answered by
6
D+E+F=?
D²EF=10DF
=>E=10DF/D²F
=E=10/D
--->ALSO,D=10/E ------Eq.1
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AGAIN,D²EF=10DF
[10/E]²EF=10DF
(100/E²)EF=10DF
100F/E=10DF {eq.2}
SOLVING RHS
10DF=10×D×F
(10×10/E)×F {FROM EQ 1}
=>100F/E
PUT VALUE OF RHS IN Eq.2
100F/E=100F/E
=>1=1
THEREFORE,
D=10/E
F=1
10/E+E+1=(10+E²+E)/E
PLEASE MARK IT AS THE BRAINIEST
Answered by
1
Answer:
d+e+f =12
hope it helps......
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