find
d the sum first 50 multiples of 5
Answers
Answered by
11
Answer:
youranswer is 250.
Step-by-step explanation:
I hope your answer is write.
Answered by
1
First number divisible by 5 = 5
Second number divisible by 5 = 10
Last number divisible by 5 before 50 = 50
Therefore, the A.P formed is
5, 10, ...., 50
Here,
a = 5
d = 10 - 5 = 5
an = a + (n-1)d
an = 50
ie, 50 = 5 + (n-1)5
After solving, we get n = 10
Sum of 1st 50 multiples of 5 = Sn
Sn = n/2(2a+(n-1)d)
After solving, we get Sn = 250
I hope this is the crt answer.
I hope this is the crt answer.Answer by Agnivesh Priyadarsanan from Kerala, India
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