Question

Find daigonal of a rectangle whose length is 35 and breadth is 12cm​

Answer 1

Answer:

$diagonal \: of \: the \: rectangle = \sqrt{ {(35)}^{2} + {(12)}^{2} } \\ = \sqrt{1225 + 144} \\ = \sqrt{1369} = 37$

Answer 2

$Length = 35cm$

$Breadth = 12cm$

$Each \: angle = {90}^{0}$

Hence , We got a right angled triangle .

In this triangle∆,

By Pythagoras Theorem ,

$\implies {diagonal}^{2} = {length}^{2} + {breadth}^{2}$

$\implies {d}^{2} = {35}^{2} + {12}^{2}$

$\implies {d}^{2} = 1225 + 144$

$\implies {d}^{2} = 1369$

$\implies d = \sqrt{1369}$

$\implies d = \sqrt{37 \times 37}$

$\implies d = 37 \: cm$

Therefore , 37 cm is the diagonal of this triangle

HØPÈ ÏT HÊLPS ♠♦♠